by Tiwari Academy
NCERT Solutions for Class 8 Maths Chapter 9 Mensuration and Class 8 Maths Chapter 9 Try These Solutions in Hindi and English Medium prepared for session 2024-25. According to new revised syllabus and latest NCERT books for CBSE 2024-25, there are only three exercises in chapter 9 of 8th NCERT Solutions of mathematics.
8th Maths Chapter 9 Solutions in English Medium
| Class: 8 | Mathematics |
| Chapter 9: | Mensuration |
| Number of Exercises: | 3 (Three) |
| Content: | NCERT Exercises Solution |
| Mode of content: | Text and Videos Format |
| Academic Session: | Year 2024-25 |
| Medium: | Hindi and English Medium |
NCERT Solutions for Class 8 Maths Chapter 9
Class VIII Mathematics Exercise 9.1, Exercise 9.2 and Exercise 9.3 in English Medium and Hindi Medium updated for new academic session following new syllabus. Download Prashnavali 9.1, Prashnavali 9.2 and Prashnavali 9.3 in Hindi Medium to study online or free PDF download. All NCERT Solutions 2024-25 are updated as per the latest CBSE Syllabus for the academic session 2024-25. Students can download NCERT Books in the PDF file format to use it offline.
App for Grade 8 Solutions
Class 8 Maths Chapter 9 Solutions
Class 8 Maths Chapter 9 Mensuration all exercises in English Medium as well as Hindi Medium are given below to study online or download in PDF format. Download NCERT Solutions offline apps, which work without internet, once downloaded. All the solutions given in apps are updated for academic session 2024-25.
Important Terms about Class 8 Maths Chapter 9
A flooring tile has the shape of a parallelogram whose base is 24 cm and the corresponding height is 10 cm. How many such tiles are required to cover a floor of area 1080 m^2? [If required you can split the tiles in whatever way you want to fill up the corners]
Base of flooring tile = 24 cm = 0.24 m
Corresponding height of a flooring tile = 10 cm = 0.10 m
Now
Area of flooring tile = Base x Altitude
= 0.24 x 0.10
= 0.024 m^2
Number of tiles required to cover the floor
= Area of Floor/Area of one tile
= 1080/0.024
= 45000 tiles
Hence 45000 tiles are required to cover the floor.
Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm. If one of the diagonals is 8 cm long, find the length of the other diagonal.
Since rhombus is also a kind of parallelogram.
Area of rhombus = Base x Altitude = 6 x 4 = 24 cm^2
Also, Area of rhombus = 1/2 x d1 x d2
According to question,
24 = 1/2 x 8 x d2
So, 4d2 = 24 and d2 = 6 cm
Hence, the length of the other diagonal is 6 cm.
In 8th Maths NCERT Chapter 9 Mensuration, we have to find the Areas, Perimeter, missing dimensions of the geometrical figures. Area of triangle, square, parallelogram, trapezium on the basis of given information and applying simple formula. Area of various specific quadrilateral like parallelogram, rhombus, rectangle, square and general quadrilateral in which we divide the quadrilateral into two triangles and then find the area of triangles and add them. Similarly we can find the area of polygon by dividing it into triangles and adding the areas of all triangles. Surface area and volumes of solid figures like Cube, Cuboids, Cylinders, Cones, etc. are given to find one the basis of application of formulae.
Do you know?
The methods used in this chapter have to be used in high school as well. Therefore, this lesson is also important from the point of view of the coming classes. Students should carefully understand all the facts used in this lesson so that there is no problem in the successive classes.
