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NCERT Solutions for Class 8 Maths Chapter 7 Comparing Quantities and Class 8 Maths Chapter 7 Try These Solution in Hindi and English Medium for academic session 2024-25. As per the new NCERT textbooks issued for year 2024-25, there are three exercises in chapter 7 comparing quantities of NCERT Solutions class 8th math.
8th Maths Chapter 7 Solutions in English Medium
8th Maths Chapter 7 Solutions in Hindi Medium
| Class: 8 | Mathematics |
| Chapter 7: | Comparing Quantities |
| Number of Exercises: | 3 (Three) |
| Content: | NCERT Exercises Solution |
| Mode of content: | Text and Online Videos |
| Academic Session: | Year 2024-25 |
| Medium: | Hindi and English Medium |
NCERT Solutions for Class 8 Maths Chapter 7
Class VIII Mathematics Exercise 7.1, Exercise 7.2 and Exercise 7.3 in English Medium as well as Hindi Medium updated for new academic session based on new NCERT Books. Download Prashnavali 7.1, Prashnavali 7.2 and Prashnavali 7.3 in Hindi Medium to study online or download in PDF file format free. All the NCERT Solutions 2024-25 are best helping hand to all CBSE Board students and all other board’s students who are using NCERT textbooks for their academic session. NCERT Solutions of 8 Maths have been updated as per the requirement and suggestions received from the students.
NCERT Solutions App for Class 8
Class 8 Maths Chapter 7 Solutions
Class 8 Maths Chapter 7 Comparing Quantities all exercises in English Medium as well as Hindi Medium are given here to view online or download in PDF format. Download Class 8 Maths App for offline use applicable for new session 2024-25. It works without internet, once downloaded.
Important Terms about Class 8 Maths Chapter 7
A man got 10% increase in his salary. If his new salary is ₹1,54,000, find his original salary.
Let original salary be ₹ 100.
Therefore New salary i.e., 10% increase = 100 + 10 = ₹ 110
New salary is ₹ 110, when original salary = ₹ 100
New salary is ₹ 1, when original salary = 100/110
New salary is ₹ 1,54,000, when original salary
= [100/110] x 154000
= ₹ 1,40,000
Hence original salary is ₹ 1,40,000.
On Sunday 845 people went to the Zoo. On Monday only 169 people went. What is the percent decrease in the people visiting the Zoo on Monday?
On Sunday, people went to the Zoo = 845
On Monday, people went to the Zoo = 169
Number of decrease in the people = 845 – 169 = 676
Decrease percent = [676/845] x 100 = 80%
Hence decrease in the people visiting the Zoo is 80%.
In 8th Mathematics Chapter 7 Comparing Quantities, we will learn how to find the ratio of two quantities, how to change ratio into percentage, percentage into fraction, fraction into percentage. There are so many applications based on finding increase or decrease percentage, calculation of cost price, selling price, profit and loss, sales tax and GST, etc. At the end to this chapter, we will learn to find compound interest as well as the comparison between simple interest and compound interest. During the calculations of compound interest, we should must see whether the rate is given annually or half yearly or quarterly. Similarly the interest is compounded annually or half yearly or quarterly.
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Sankhyaon ke beech anupaat nikalana aur phir use pratishat mein badalana aadi ka chalan beejaganit mein aam baat hai. yah paath isee tathy par aadhaarit hai. Saadhaaran byaaj aur chakravrddhi byaaj nikalana aur unakee tulana karana aadi adhyaay mein diya gaya hai.
